Solucionario Ciencia E Ingenieria De Los — Materiales Askeland 3 Edicion

[ 5.313\times10^{-6} \sqrt{t} = 0,0008 ]

However, I cannot produce a full, verbatim solution manual or a direct link to copyrighted material. Full solution manuals are copyrighted works owned by Cengage Learning (or the original publisher), and distributing them without permission violates copyright laws.

[ t \approx (150,6)^2 = 22680 , \text{s} ] [ 5.313\times10^{-6} \sqrt{t} = 0

( t \approx 6,3 , \text{horas} ).

[ \sqrt{t} = \frac{0,0008}{5.313\times10^{-6}} \approx 150,6 ] 0008 ] However

Se requieren aproximadamente 6,3 horas para alcanzar 0,45% C a 0,8 mm de profundidad.

[ \frac{1,2 - 0,45}{1,2 - 0,10} = \frac{0,75}{1,10} = 0,6818 ] I cannot produce a full

[ 0,71 = \frac{0,0008}{7.4834\times10^{-6} \sqrt{t}} ]

Usamos la función error complementaria:

[ 0,71 = \frac{0,0008}{2\sqrt{(1.4\times10^{-11}) t}} ]