At max height, ( v = 0 ). Use ( v^2 = v_0^2 + 2a(s - s_0) ): [ 0 = 20^2 + 2(-9.81)(s_\textmax - 50) ] [ 0 = 400 - 19.62(s_\textmax - 50) ] [ 19.62(s_\textmax - 50) = 400 ] [ s_\textmax - 50 = 20.387 ] [ \boxeds_\textmax = 70.387 , \textm ]
Topics: Dynamics, Engineering Mechanics, Calculus-Based Kinematics What is Rectilinear Motion? Rectilinear motion refers to the movement of a particle along a straight line. In engineering mechanics, this is the simplest form of motion. The position of the particle is described by its coordinate ( s ) (often measured in meters or feet) along the line from a fixed origin.
[ v = v_0 + at ] [ s = s_0 + v_0 t + \frac12 a t^2 ] [ v^2 = v_0^2 + 2a(s - s_0) ] rectilinear motion problems and solutions mathalino
Use ( v = v_0 + at ): [ 0 = 20 - 9.81 t \quad \Rightarrow \quad t = \frac209.81 \approx \boxed2.038 , \texts ]
Use ( a = v \fracdvds = -0.5v ). Cancel ( v ) (assuming ( v \neq 0 )): At max height, ( v = 0 )
[ \int dv = \int 6t , dt ] [ v = 3t^2 + C_1 ]
From ( v = \fracdsdt = 20 - 0.5s ). Separate variables: In engineering mechanics, this is the simplest form
At ( t = 0 ), ( v = 0 \Rightarrow C_1 = 0 ). Thus: [ \boxedv(t) = 3t^2 ]
[ \int ds = \int 3t^2 , dt ] [ s = t^3 + C_2 ]
[ v , dv = 4s , ds ] Integrate: [ \fracv^22 = 2s^2 + C ] At ( s = 1 ) m, ( v = 0 ): [ 0 = 2(1)^2 + C \quad \Rightarrow \quad C = -2 ] Thus: [ \fracv^22 = 2s^2 - 2 ] [ v^2 = 4s^2 - 4 ] [ \boxedv(s) = \pm 2\sqrts^2 - 1 ]